s^2=1120

Solution for s^2=1120 equation:

s^2=1120

We move all terms to the left:

s^2-(1120)=0

a = 1; b = 0; c = -1120;
Δ = b2-4ac
Δ = 02-4·1·(-1120)
Δ = 4480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4480}=\sqrt{64*70}=\sqrt{64}*\sqrt{70}=8\sqrt{70}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{70}}{2*1}=\frac{0-8\sqrt{70}}{2}
=-\frac{8\sqrt{70}}{2}
=-4\sqrt{70}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{70}}{2*1}=\frac{0+8\sqrt{70}}{2}
=\frac{8\sqrt{70}}{2}
=4\sqrt{70}
$